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Monday, 14 October 2013

// // 4 comments

10 bit A/D converters, the quantization error is given by (in Percent)-HAL 2011

communication systemsA) 1

B) 2

C) 0.1

D) 0.2

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4 comments:

  1. .1%...............since quantiztion error is given by (1/no of step size).
    total no of step size -2^n where n is the no of bit...
    2^10=1024
    q=(1/1024)
    ie .1%

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    Replies
    1. As per my knowledge Quantization error is given as + - (Step Size)/2
      Step size= Vpp/2^10 = Vpp/1024
      Qe=Vpp/2048

      Percentage Qe= 1/2048 ~ 0.05%

      Where I am making mistake?

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    2. Step Size is Vmax-Vmin i.e., 2v i.e,2v/2048

      Delete