10 bit A/D converters, the quantization error is given by (in Percent)-HAL 2011
A) 1
B) 2
C) 0.1
D) 0.2
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.1%...............since quantiztion error is given by (1/no of step size).
ReplyDeletetotal no of step size -2^n where n is the no of bit...
2^10=1024
q=(1/1024)
ie .1%
As per my knowledge Quantization error is given as + - (Step Size)/2
DeleteStep size= Vpp/2^10 = Vpp/1024
Qe=Vpp/2048
Percentage Qe= 1/2048 ~ 0.05%
Where I am making mistake?
Step Size is Vmax-Vmin i.e., 2v i.e,2v/2048
Deletei m agree with above answer.
ReplyDelete